You can not select more than 25 topics Topics must start with a letter or number, can include dashes ('-') and can be up to 35 characters long.
ML_ITK/CONNOR_ITK/ItemIsMeetTheConditions.cxx

116 lines
2.9 KiB

This file contains ambiguous Unicode characters!

This file contains ambiguous Unicode characters that may be confused with others in your current locale. If your use case is intentional and legitimate, you can safely ignore this warning. Use the Escape button to highlight these characters.

#define _CRT_SECURE_NO_WARNINGS
#include "epm_handler_common.h"
/*************************************************************************************************
* ML_ItemIsMeetTheConditions()
*
* Description:
* This handler will Determine whether the object meets the condition
*
* Syntax:
*
* -property: 判断属性item.item_id,rev.,revMaster.
*
* -value: 属性对应的值1111,2222
*
* -type: 判断类型(等于/不等于)
*
* Placement:
* no request
*
**************************************************************************************************/
int ML_ItemIsMeetTheConditions(EPM_action_message_t msg) {
printf("=========================判断对象是否满足条件 Start===================\n");
int ifail = ITK_ok;
int attachments_num = 0;
tag_t rootTask = NULLTAG, *attachments = NULLTAG;
//获取任务对象
EPM_ask_root_task(msg.task, &rootTask);
//获取任务目标对象
EPM_ask_attachments(rootTask, EPM_target_attachment, &attachments_num, &attachments);
char *argflag = NULL, *argvalue = NULL, *arg = NULL;
char arg1value[1024] = "", arg2value[1024] = "", arg3value[1024] = "";
//获取参数
int arg_cnt = TC_number_of_arguments(msg.arguments);
printf("参数个数为:%d\n", arg_cnt);
if (arg_cnt > 0)
{
for (int i = 0; i<arg_cnt; i++)
{
//获取下一个参数从0开始
arg = TC_next_argument(msg.arguments);
//获取参数的名称和值
ifail = ITK_ask_argument_named_value((const char*)arg, &argflag, &argvalue);
if (stricmp(argflag, "property") == 0)
{
//strcmp("","");
if (argvalue != NULL)
{
strcpy(arg1value, argvalue);
}
}
else if (stricmp(argflag, "value") == 0)
{
if (argvalue != NULL)
{
strcpy(arg2value, argvalue);
}
}
else if (stricmp(argflag, "type") == 0)
{
if (argvalue != NULL)
{
strcpy(arg3value, argvalue);
}
}
}
}
int propertyCount = 0;
char ** propertyChar = new char *[64];
//分割字符串
split(arg1value, ",", propertyChar, &propertyCount);
int valueCount = 0;
char ** valueChar = new char *[64];
//分割字符串
split(arg2value, ",", valueChar, &valueCount);
for (int i = 0; i < attachments_num; i++)
{
for (int j = 0; j < propertyCount; j++)
{
char * property = propertyChar[j];
if (strstr(property, ".") != NULL)
{
int itemCount = 0;
char ** itemChar = new char *[64];
split(property, ".", itemChar, &itemCount);
char * value = NULL;
if (strcmp(itemChar[0], "item") == 0)
{
//获取对象
AOM_ask_value_string(attachments[i], itemChar[1], &value);
}
else if (strcmp(itemChar[0], "rev") == 0)
{
AOM_ask_value_string(attachments[i], itemChar[1], &value);
}
else if (strcmp(itemChar[0], "revMaster") == 0)
{
AOM_ask_value_string(attachments[i], itemChar[1], &value);
}
}
}
}
DOFREE(attachments);
printf("=========================判断对象是否满足条件 End===================\n");
return ifail;
}